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-3(Y^2-2Y+3)=Y
We move all terms to the left:
-3(Y^2-2Y+3)-(Y)=0
We add all the numbers together, and all the variables
-1Y-3(Y^2-2Y+3)=0
We multiply parentheses
-3Y^2-1Y+6Y-9=0
We add all the numbers together, and all the variables
-3Y^2+5Y-9=0
a = -3; b = 5; c = -9;
Δ = b2-4ac
Δ = 52-4·(-3)·(-9)
Δ = -83
Delta is less than zero, so there is no solution for the equation
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